1.

Tungsten crystallizes in a body centred cubic unit cell. If the edge of the unit cell is 316.5 pm, what is the radius of the tungsten atom?

Answer»

Solution :a = 316.5 pm
For BCC STRUCTURE, `R=(sqrt3)/(4)a=(sqrt3)/(4) xx 316.5` pm
= 317.04 pm


Discussion

No Comment Found