Turpentine oil is flowing through a tube of length ′l′ and radius ′r′ . The pressure difference between the two ends of the tube is P. The viscosity of oil is given by η=P(r2−x2)4vl, where v is the velocity of oil at a radial distance 'x' from the axis of the tube. The dimensions of η are

Turpentine oil is flowing through a tube of length ′l′ and radius

1.	Turpentine oil is flowing through a tube of length ′l′ and radius ′r′ . The pressure difference between the two ends of the tube is P. The viscosity of oil is given by η=P(r2−x2)4vl, where v is the velocity of oil at a radial distance 'x' from the axis of the tube. The dimensions of η are
Answer» Turpentine oil is flowing through a tube of length $^{'} l^{'}$ and radius $^{'} r^{'}$ . The pressure difference between the two ends of the tube is $P$ . The viscosity of oil is given by $η = \frac{P (r^{2} - x^{2})}{4 v l}$ , where $v$ is the velocity of oil at a radial distance ' $x$ ' from the axis of the tube. The dimensions of $η$ are

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