Twice a number when decreased by 7 gives 45. Find the number. – InterviewSolution

1.

Twice a number when decreased by 7 gives 45. Find the number.

Answer»

Let the required number be x.Then,

= 2x – 7 = 45

Transposing -7 to RHS and it becomes 7.

= 2x = 45 + 7

= 2x = 52

Multiplying both side by (1/2)

= 2x × (1/2) = 52 × (1/2)

= x = 26

∴ The required number is 26.

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