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Two 20V Batteries are connected in series to two resistors which are in parallel. Values of the resistors are 20 and 25 ohms. Draw the circuit diagram for this scenario. Find the current flowing through the circuit. |
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Answer» AnswerThe current in the 10Ω resistance ISI 1 = R 1 +R 2 R 2 i= 20+10(20)×(6) =4AThe current in the 20Ω resistor isi 2 = R 1 +R 2 R 1 i= 10+2010×6 =2AOremf across 10Ω resistorV 1 =i 1 ×10emf across 20Ω resistorV 2 =i 2 ×20Since i 1 +i 2 =6A and V 1 =V 2 , we have i 1 =4Ai 2 =2A |
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