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Two acids H_(2)SO_(4) and H_(3)PO_(4) are neutralized seqarately by the same amount of an alkali when sulphate and dihydrogen orthophosphate are formed respectively. Find the ratio of the masses of H_(2)SO_(4) and H_(3)PO_(4)? (P = 31) |
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Answer» Solution :1 g eq of alkali will neutralize 1 g eq. of `H_(2)SO_(4)` and 1 g eq. of `H_(3)PO_(3)`. For the given neutralisation reactions `H_(2)SO_(4)+2NaOHrarr Na_(2)SO_(4)+2H_(2)O` `"and"H_(3)PO_(4)+NAOH rarr NaH_(2)PO_(4)+H_(2)O` `"Eq. mass of "H_(2)SO_(4)=("Mol. mass")/(2)=(98)/(2)=49` and Eq. mass of `H_(3)PO_(4)=("Mol. mass")/(1)=(98)/(1)=98` As the substances REACT in the RATIO of their equivalent MASSES, hence, the ratio of masses of `H_(2)SO_(4)` and `H_(3)PO_(4)=49:98=1:2`. |
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