Saved Bookmarks
| 1. |
Two alloys both are made up ofcopper and tin. The ratio ofcopper and tin in the first alloyis 1: 3 and in the second alloyis 2 5. In what ratio should thetwo alloys be mixed to obtain anew alloy in which the ratio oftin and copper be 8:3? |
|
Answer» Given:⇔ Let the alloys be mixed in the ratio ofX :Y(Assumption)⇔ In 1st alloy, Copper = x/4⇔ In 1st alloy, Tin = 3x/4⇔ In 2nd alloy, Copper = 2y/7⇔ In 2nd alloy, Tin = 5y/7 To find:⇔ Ratio in which 2 alloys must be mixed to get a new alloy with ratio of copper and tin be 3 : 8= ? Solution:⇔ Now we have,⇒ (x/4 + 2y/7) : (3x/4 + 5y/7) = 3 : 8⇒ (x/4 + 2y/7) / (3x/4+ 5y/7) = 3/8⇒ (7x + 8y/28) / (21x + 20y/28) = 3/8⇒ (7x + 8y) / (21x + 20y) = 3/8⇒ 8 (7x + 8y) = 3 (21x + 20y)⇒ 56x + 64y = 63x + 60y⇒ 64y - 60y = 63x - 56x⇒ 4y = 7x⇒∴x/y = 4/7 ⇒ Ratio in which 2 alloys must be mixed to get a new alloy withratioof copper and tin be3 :8=4/7 thank you for listening fast reply lightening* |
|