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Two ammeters, one with a full-scale current of 1 mA and internal resistance of 100 Ω and other a full-scale current of 10 mA and internal resistance of 25 Ω are in parallel. What is the total current, these two meters can carry without the reading out of scale in any meter?(a) 1 mA(b) 10 mA(c) 11 mA(d) 5 mAThis question was addressed to me in an online interview.My doubt stems from Advanced Problems on Indicating Instruments in division Extension of Instrument Ranges of Electrical Measurements

Answer»

Right option is (d) 5 mA

To EXPLAIN I would say: The lower current Il will DECIDE the total current.

∴ T × \(\frac{25}{125}\) = 1 mA

Or, T = 5 mA.



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