1.

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.

Answer»

Given that,

Two angles are equal and third angle is greater than each of those angles by 30°.

Let, x, x, x + 30° be the angles of the triangle.

We know that,

Sum of all angles of triangle is 180°

x + x + x + 30° = 180°

3x + 30° = 180°

3x = 180° – 30°

3x = 150°

x = 50°

Therefore,

The angles are:

x = 50°

x = 50°

x + 30° = 50° + 30°

= 80°

Therefore, the required angles are 50°, 50°, 80°.



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