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Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle. |
Answer» Given that, Two angles are equal and third angle is greater than each of those angles by 30°. Let, x, x, x + 30° be the angles of the triangle. We know that, Sum of all angles of triangle is 180° x + x + x + 30° = 180° 3x + 30° = 180° 3x = 180° – 30° 3x = 150° x = 50° Therefore, The angles are: x = 50° x = 50° x + 30° = 50° + 30° = 80° Therefore, the required angles are 50°, 50°, 80°. |
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