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Two balls are dropped from the same height at two different places A and B where the acceleration due to gravities are g_A and g_B . The body at 'B' takes 't' seconds less to reach the ground and strikes the ground with a velocity greater than at 'A” by v m/s. Then the value of 'v/t' is |
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Answer» `(1)/(SQRT(g_A g_B))` |
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