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Two balls are dropped from the same height at two different places A and B where the acceleration due to gravities are g_A and g_B. The body at .B. takes t. seconds less to reach the ground and strikes the ground with a velocity greater than at .A" by v m/s. Then the value of .v/t. is |
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Answer» `(1)/SQRT(g_(A)g_(B))` |
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