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Two balls are projected at an angle `theta` and `(90^(@) - theta)` to the horizontal with the same speed. The ratio of their maximum vertical heights isA. ` 1 : 1`B. `tan theta : 1`C. `1 : tan theta`D. `tan^(2)theta : 1` |
Answer» Correct Answer - D `H_(1) = (u^(2)sin^(2)theta)/(2g)" "...(i)` `H_(2) = (u^(2)sin^(2) (90^(@) -theta))/(2g) = (u^(2) cos^(2)theta)/(2g) " "...(ii)` Divide (i) by (ii), we get `(H_(1))/(H_(2)) = (tan^(2)theta)/(1)` |
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