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Two balls of equal masses are thrown upwards, along the same vertical direction at an interval of 2 seconds, with the same initial velocity of `40m//s`. Then these collide at a height of (Take `g=10m//s^(2)`).A. 50 mB. 75 mC. 100 mD. 125 m |
Answer» Correct Answer - D `s_1=s_2` `:. (40)t-1/2xx10xxt^2=(40)(t-2)` `-1/2xx10xx(t-2)^2` Solving this equation, we get `t=5s` Then `s_1=(40)(5)-1/2xx10xx(5)^2` `=75m` |
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