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Two beams of ligth having intensities I and 4I interface to produce a fringe pattern on a screen. The phase difference between the beams is `(pi)/(2)` at point A and `pi` at point B. Then the difference between the resultant intensities at A and B isA. `2I`B. `4I`C. `5I`D. `9I` |
Answer» Correct Answer - B `DeltaI=(I_(1)+I_(2)+2sqrt(I_(1)I_(2))cosphi_(1))-(I_(1)+I_(2)+2sqrt(I_(1)I_(2))cosphi_(2))` `=2sqrt(I_(1)I_(2))(cosphi_(1)-cosphi_(2))=2xx2I("cos"phi/2-cospi)=4I` |
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