1.

Two billiard balls of the same size (radius r) and same mass are in contact on a billiard table. A third ball also of the same size and mass strikes them symmetrically and remains at rest after the impact. The coefficient of restitution between the balls is

Answer»

Solution :`sin theta =(r )/(2R) = (1)/(2), THEREFORE 3 = 30^(@)`
From conservation of linear momentum
`m u = 2 mv = cos 30^(@) or v = (u)/(sqrt3)`
Now ` E = ("relative velocity of separation")/("relative velocity of approach")` in common normal direction
HENCE, `e = (v )/( u cos 30 ^(@)) = (u // sqrt3)/( u sqrt3 //2) = 2/3`


Discussion

No Comment Found