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Two blocks A and B of masses 2 kg and 3kg are connected by a light string as shown in the figure and place on a horizontal surface. mu between all surface is 0.1 and g = 10 ms^(-2). The acceleration of the system is, when the force applied F = 45 N. |
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Answer» Solution :`F-mu (m_(1)+m_(2))g=(m_(1)+m_(2))` `45-0.1(5)10=5a` `45-5=5a` `a=8 MS^(-2)`
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