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Two blocks are connected over a massless pulley as shown in figure. The mass of block A is 10 kg and the coefficient of kinetic friction is 0.2 Block A sliders down the incline at constant speed. The mass of block B in kg is |
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Answer» 5.4 `m_(A)g sin 30^(@)=mu m_(A)g cos 30^(@)+m_(B)g` `therefore"" m_(B)=((m_(A))/(2))-((mu m_(A)sqrt(3))/(2))` `=10[(1)/(2)-0.2xx(sqrt(3))/(2)]=3.3 kg ` |
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