Two blocks of m asses 6 kg and 2 kg are placed in contact on a horizontal frictionless surface. If a horizontal force of 2N is applied to m ass 6 kg to move them together, what will be the acceleration of 2 kg block ? What will be the force on this block ?

Two blocks of m asses 6 kg and 2 kg are placed in contact on a horizon

1.	Two blocks of m asses 6 kg and 2 kg are placed in contact on a horizontal frictionless surface. If a horizontal force of 2N is applied to m ass 6 kg to move them together, what will be the acceleration of 2 kg block ? What will be the force on this block ?
Answer» Solution : ACCELERATIONOF the systemof twoblock `a= ("totalforce")/("total mass ") = (F)/( m_(1) +m_(2)) = (2 ) /(6+2)= (2)/(8)= 0.25 MS^(-2)` Forceon 2 kgblockF= `m_(2)a = 2xx0.025=0.50 N`