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Two blocks of mass 4kg and 6kg are connected by a string as shown in the figure . They are initially at rest on the floor . Calculate their acceleration when a force of (a) 50N (b) 100N is applied on the pulley. |
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Answer» Solution :Case (i): FORCE on 6kg and 4kg object` =F/2=25N`. The APPLIED froce in each block is less than the WEIGHT of each block . So the blocks will not move Case (ii): Force on each block `=(100)/2=50N`. The 6kg block will not move because applied force is less than its weight . On 4kg mass Resutant force = mass X acceleration `50-40=a ,10=4a ,a=2.5 m//s^(2)` |
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