1.

Two blocks of mass 4kg and 6kg are connected by a string as shown in the figure. They are initially at rest on the floor. Calculate their acceleration when a force of (a) 50N (b) 100N is applied on the pulley.

Answer»

Solution : Case(i):
Force on 6KG and 4 kg object ` = (F)/(2)= 25N`.
The APPLIED force on each block is less than the weight of each block. So the blocks will not move.
Case (ii):
A 50N Force on each block `=(100)/(2)` = 50N.
The 6kg block will not move because applied force is less than its weight.
On 4 kg mass
RESULTANT force = mass `xx` acceleration
`50-40 = 4a, 10 = 4a , a=2.5 m//s^(2)`


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