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Two blocks of mass 4kg and 6kg are connected by a string as shown in the figure. They are initially at rest on the floor. Calculate their acceleration when a force of (a) 50N (b) 100N is applied on the pulley. |
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Answer» Solution : Case(i): Force on 6KG and 4 kg object ` = (F)/(2)= 25N`. The APPLIED force on each block is less than the weight of each block. So the blocks will not move. Case (ii): A 50N Force on each block `=(100)/(2)` = 50N. The 6kg block will not move because applied force is less than its weight. On 4 kg mass RESULTANT force = mass `xx` acceleration `50-40 = 4a, 10 = 4a , a=2.5 m//s^(2)`
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