InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Two blocks of masses `1 kg` and `2 kg` are connected by a metal wire goijng over a smooth pulley as shown in figure. The breaking stress of the metal is `(40//3pi)xx10^(6)N//m^(2)`. If `g=10ms^(-12)`, then what should be the minimum radlus of the wire used if it is not to break? A. `0.5mm`B. `1mm`C. `1.5mm`D. `2mm` |
|
Answer» Correct Answer - B `T=(2m_(1)m_(2))/(m_(1)+m_(2))g=(2xx1xx2)/(1+2)xx10N=40/3N` If `r` is the minimum radius, then Breaking stress `=(40/3)/(pir^(2))` or `40/(3pi)xx10^(6)=40/(3pir^(2))` or `r^(2)=1/(10^(6))` or `r=1/(10^(3))m` or `r=1/(10^(3))xx10^(3)m=1mm` |
|