1.

Two blocks of masses 10 kg and 30 kg are placed along a vertical line. If the first block is raised through a height of 7 cm, by what distance should the second mass be moved to raise the centre of mass by 1 cm.

Answer»

Solution :`m_(1)=10 kg, m_(2)=30 kg`
`Deltax_(cm) =(m_(1)(Deltax_(1)) + m_(2)(Deltax_(2)))/(m_(1) + m_(2)), 1=(10(7) + 30(Deltax_(2)))/(10 + 30) rArr Deltax_(2) =-1 cm`
Here "-ve" sign indicates that .`m_(2)`. be MOVED in opposite direction, i.e., `m_(2)`is lowerd by 1 cm.


Discussion

No Comment Found