1.

Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m's to the heavier block in the direction of the lighter block. The velocity of the center of mass is

Answer»

30 m/s
20 m/s
10 m/s
5 m/s

Solution :According to law of conservation of LINCAR MOMENTUM
`MV=(M+M)V_(CM)`
`:.V_(CM)=(MV)/((M+M))=(10xx14)/(10+4)=10 MS^(-1)`


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