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Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of `14 m//s` to the heavier block in the direction of the lighter block. The velocity of the centre of mass isA. `30 m//s`B. `20 m//s`C. `10 m//s`D. `5 m//s` |
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Answer» Correct Answer - C Just after collision `v_(c ) = (10 xx 14 + 4 xx 0)/(10 + 4) = 10 m//s` since spring force is internal force, it cannot change the linear momentum of the (two mass + spring) system. Therefore `v_(c )` remains the same. |
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