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Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of `14 m//s` to the heavier block in the direction of the lighter block. The velocity of the centre of mass isA. `30m//s`B. `20 m//s`C. `10 m//s`D. `5 m//s` |
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Answer» Correct Answer - C Just after giving the impulse: `V_(c)=(10xx14+4xx10)/(10+4)=10m/s` Since spring force is internal force it cannot change the linear momentum of the (two mass `=` spring) system. Therefore `V_(c)` remains the same |
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