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Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a friction less horizontal surface. An impulse gives a velocity of 14 m s-1 to the heavier block in the direction of the lighter block. The velocity of the centre of mass is (a) 30 m s-1 (b) 20 m s-1 (c) 10 m s-1 (d) 5 m s-1 |
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Answer» Correct Answer is: (c) 10 m s-1 vCM = m1v1 + m2v2 / m1 + m2 = (10Kg)(14 m s-1) + (4 Kg) /10 Kg + 4 Kg = 10 m s-1. |
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