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Two blocks of masses M_(1) and M_(2) connected by a light spring rest on a horizontal plane . The coefficient of friction between the blocks and the surface is equal to mu . The minimum constant force that has to be applied in the horizontal direction to the block of mass M_(1) in order to shift the other block is (M_(1) + (M_(2))/(alpha)) mu g, then alphais : |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_AM_PHY_C07_E01_154_S01.png" width="80%"/> <br/> `F = <a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> M_(1) <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> + T "" ….(i)` <br/> `T = muM_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) g "" …..(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)` <br/> By solving , we get `alpha`.</body></html> | |