Saved Bookmarks
| 1. |
Two blocks of masses m_(1) and m_(2) in contact lie on a horizontal smooth surface as shown in The blocks are pushed by a force F If the two blocks are always in contact what is the force at their common interface . |
|
Answer» `:. A = (F)/(m_(1) m_(2))` If f is force EXERTED by `m_(1)` on `m_(2)` then force exerted by `m_(2)` on `m_(1)` is (-) f , as SHOWN in As block of mass `m_(2)` has accelera- tio a `:. f = m_(2) a = (m_(2) xx F)/(m _(1) + m_(2)` .
|
|