1.

Two blocks of masses m1, m2 are connected by a light spring on a smooth horizontal surface. The two masses are pulled apart and the released. Prove that the ratio of their acceleration are inversely proportional to their masses.

Answer»

The forces F1 and F2 due to masses m1 and m2 respectively act on the stretched spring in opposite directions. Thus, the system as a whole is at

Thus F1 + F2 = 0

or, m1a1 + m2a2 = 0

Where a1 and a2 are accelerated of the masses m1 and m2 respectively in the opposite direction.

Now, m1a1 = -m2a2

or, a1/a2 = -m2/m1

which was to be established.



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