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Two blocks of masses m1, m2 are connected by a light spring on a smooth horizontal surface. The two masses are pulled apart and the released. Prove that the ratio of their acceleration are inversely proportional to their masses. |
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Answer» The forces F1 and F2 due to masses m1 and m2 respectively act on the stretched spring in opposite directions. Thus, the system as a whole is at Thus F1 + F2 = 0 or, m1a1 + m2a2 = 0 Where a1 and a2 are accelerated of the masses m1 and m2 respectively in the opposite direction. Now, m1a1 = -m2a2 or, a1/a2 = -m2/m1 which was to be established. |
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