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Two blocks of wood of masses `m_(1) and m_(2)` and each of specific givity 0.5 are submerged at a depth of `h_(1) and h_(2)` in v vessel `(h_(2)gth_(1))` filled with water, which is accelerated upwards with an acceleration g/2. The difference in time taken by the blocks to reach the surface, when frleased with zero velocity isA. zeroB. `2sqrt(((h_(2)-h_(1)))/(2g))`C. `sqrt(((h_(2)-h_(1)))/(g))`D. `2sqrt(((h_(2)-h_(1)))/(3g))` |
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Answer» Correct Answer - D `a_(1)=("upthrust-weight")/(m)=2g` similarly `a_(2) = 2g` Acceleration relative to water = 3g/2 `t_(l)=2sqrt((h_(1))/(3g))` `t_(2)=2sqrt((h_(2))/(3g))` `thereforet_(2)-t_(1)=2sqrt(((h_(2)-h_(1)))/(3g))` |
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