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Two bodies A and B of equal masses are kept at heights of h and 2h respectively. What will be the ratio of their potential energies? |
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Answer» Let the masses of A and B = m Height of A = h Height of B = 2h Potential energy for body A, PEA = mgh Potential energy for body B, PEB = mg2h Ratio = PEA : PEB = (mgh)/(mg2h) = ½ |
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