Two bodies A and B whose masses are in the ratio 1:2 are suspended from two separate massless springs of force constants k_(A) and k_(B) respectively. If the two bodies oscillate vertically such that their maximum velocities are in the ratio 1:2 the ratio of the amplitude A to that of B is :

Two bodies A and B whose masses are in the ratio 1:2 are suspended fro

1.	Two bodies A and B whose masses are in the ratio 1:2 are suspended from two separate massless springs of force constants k_(A) and k_(B) respectively. If the two bodies oscillate vertically such that their maximum velocities are in the ratio 1:2 the ratio of the amplitude A to that of B is :
Answer» `SQRT((k_(B))/(2k_(A)))` `sqrt((k_(B))/(8k_(A)))` `sqrt((2k_(B))/(k_(A)))` `sqrt((8k_(B))/(k_(A)))` SOLUTION :`v_(A)=:v_(B)=1:2` AMPLITUDE of A : Amplitude of `B=sqrt(K_(B)), sqrt(8K_(A))`