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Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 28g and its density is 5.6g/c.c. If the mass of the other body is 36g, find its density d. |
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Answer» SOLUTION :Weight of WATER DISPLACED by first body = `(28)/(5.6)g`, Weight of water displaced by second body = `(36)/(d)g`, Apparent weight of first body = `(28-(28)/(5.6))g` Apparent weight of second body = `(36-(36)/(d))g` since bodies are in equilibrium `(28-(28)/(5.6))g=(36-(36)/(d))g""d=(36)/(13)~~2.8g//c c`. |
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