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Two bodies are projected vertically upwards from one point with the same initial velocity `v_0.` The second body is projected `t_0 s` after the first. How long after will the bodies meet? |
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Answer» Correct Answer - B At the time of collision, `s_1=s_2` `:. v_0t-1/2g t^2=v_0(t-t_0)-1/2g(t-t_0)^2` Solving this equation we get, `t=(v_0)/g+(t_0)/2` |
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