1.

Two bodies begin to fall freely from the same height. The second body begins to fall 'tau' s after the first. After what time from the beginning of first body does the distance between the bodies equal to l?

Answer»

Solution :LET the time of fall of the 1st body be t SECONDS.
Time of fall of second body = `t=tau`.
Distance of FREE fall of the bodies in the above time intervals respectively are
`H_(1)=(g t^(2))/(2),H_(2)=(g(t-tau)^(2))/(2)`
THEREFORE `L=H_(1)-H_(2)=g t tau-(1)/(2)g tau^(2)`
`therefore t=(l)/(g tau)+(tau)/(2)`


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