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Two bodies of mass 60 kg and 30 kg moving in the same direction along straight line velocity 40cms^(-1) and 30cms^(-1)respectively suffer one dimensional elastic collision. Find their velocities after collision |
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Answer» Solution :`"Mass "m_(1)=60KG , "Mass" m_(2)=30KG ,v_(1)=40cms_(-1) ,v_(2)=30 cms^(-1)` `v_(1)((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)+((2m_(1))/(m_(1)-m_(2)))u_(2)` `v_(2)=((m_(2)-m_(1)))/(m_(1)+m_(2))=u_(2)+ ((2M^(2))/(m_(1)+m_(2)))u_(2)` Substituting the values, we get , `v_(1)=(60-30)/90xx40+(2xx30)/90xx30` `v_(1)=1/9[1200+1800]=(39000)/90=33.3cm s^(-1)` likewise, `v_(2)=(30-60)/90xx30+(2xx60)/90xx40` `v_(2)=1/9[1200+18000]=(3900)/90=43.3cm s^(-1)` |
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