Saved Bookmarks
| 1. |
Two bodies of masses 15 kg and 10 kg are connected with light string kept on a smooth surface. A horizontal force F = 500 N is applied to a 15 kg as shown in the figure. Calculate the tension acting in the string. |
|
Answer» Given, m1 = 15 kg, m2 = 10 kg, F = 500 N Tension acting in the string T = \(\frac{m_2}{m_1 + m_2}\) F T = \(\frac{10}{25}\) x 500 = 200 N |
|