Two bodies of masses m_(1) and m_(2) are moving with velocities 1 ms^(-1) and 3ms^(-1) respectively in opposite directions. If the bodies undergo one dimensional elastic collision, the body of mass m_(1) comes to rest. Find the ratio of m_(1) and m_(2).

Two bodies of masses m_(1) and m_(2) are moving with velocities 1 ms^(

1.	Two bodies of masses m_(1) and m_(2) are moving with velocities 1 ms^(-1) and 3ms^(-1) respectively in opposite directions. If the bodies undergo one dimensional elastic collision, the body of mass m_(1) comes to rest. Find the ratio of m_(1) and m_(2).
Answer» Solution :`u_(1)=1 ms^(-1), u_(2)= -3 ms^(-1), v_(1)=0` `v_(1) = ((m_(1) -m_(2))/(m_(1) + m_(2)))u_(1) + ((2m_(2))/(m_(1) + m_(2)))u_(2)` `0 = ((m_(1)-m_(2))/(m_(1) + m_(2)))1 + ((2m_(2))/(m_(1) + m_(2)))(-3)` `m_(1)-m_(2)= 6m_(2), m_(1)= 7 m_(2), (m_(1))/(m_(2))= (7)/(1)`