Saved Bookmarks
| 1. |
Two bodies of masses m_(1) and m_(2) are moving with velocities 1ms^(-1) and 3ms^(-1) respectively in opposite directions. If the bodies undergo one dimensional elastic collision, the body of mass m_(1) comes to rest. Final the ratio of m_(1) and m_(2). |
|
Answer» Solution :`u_(1)=1ms^(-1),u_(2)=-3ms^(-1),v_(1)=0` `v_(1)=((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)+((2m^(2))/(m_(1)+m^(2)))u_(2)` `0=((m_(1)-m_(2))/(m_(1)+m_(2)))1+((2m^(2))/(m_(1)+m^(2)))(-3)` `m_(1)-m_(2)=6m_(2), "" m_(1)=7m_(2),(m_(1))/(m_(2))=(7)/(1)` |
|