Two bodies of masses m_(1)and m_2 (m_1 gt m_2) respectively are tied to the ends jof a string which passes over a light frictionless pulley. The masses are intitially at rest and released. What is the acceleration of the centre of mass ?

Two bodies of masses m_(1)and m_2 (m_1 gt m_2) respectively are tied t

1.	Two bodies of masses m_(1)and m_2 (m_1 gt m_2) respectively are tied to the ends jof a string which passes over a light frictionless pulley. The masses are intitially at rest and released. What is the acceleration of the centre of mass ?
Answer» SOLUTION :`(m_(1) + m_(2)) veca_("cm") = m_(1)veca_(1) + m_(2)veca_(2) = m_(1)VECA - m_(2)veca = (m_(1)-m_(2))a = (m_(1)-m_(2))(m_(1)- m_(2))vecg lm_(1) + m_(2) veca_("cm") = (m_(1)- m_(2))^(2)vecg//(m_(1) + m_(2))^(2)`.