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Two bodies of masses m and M are placed at distance d apart. The gravitational potential (V) at the position where the gravitational field due to them is zero V isA. `V=-(G)/(d)(m+M)`B. `V=-(Gm)/(d)`C. `V=-(GM)/(d)`D. `V=-(G)/(d)(sqrt(m)+sqrt(M))^(2)` |
Answer» Correct Answer - D `E_("net")=0` `:. (Gm)/(x^(2))=(GM)/((d-x)^(2)),x` is distance from `m` `:. (x)/(d-x)=(sqrt(m))/(sqrt(M))rArrx=(sqrt(m))/(sqrt(m)+sqrt(M)),d` and `d-x=(sqrt(M))/(sqrt(m)+sqrt(M)).d` Since, gravitational potential between two bodies of masses M and m respectively, is given by `V=-(Gm)/(x)-(GM)/(d-x)` `=-(GM(sqrt(m)+sqrt(M)))/(sqrt(m).d)-(GMsqrt(m)+sqrt(M))/(sqrt(M).d)=-(G)/(d)(sqrt(m)+sqrt(M))^(2)`. |
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