Saved Bookmarks
| 1. |
Two bodies start moving in the same straight line at the same instant of time from the same origin. The first body moves with a constant velocity of 40 m/s, and the second starts from rest with a constant acceleration of 4m/s""^2. Find the time that elapses before the second catehes the firs body. Find also the greatest distance between der prior to ir and the time at which this occurs. |
|
Answer» SOLUTION :When the second body catches the first, the DITANCE TRAVELLED by each is the same. `40t=1/2(4)t^(2) or t=20S` Now, the distance s between the two bodies at any time t is `s=ut-1/2at^(2)` For s to be maximum. `(DS)/(dt)=0 or u-at=0` `or t=u/a=(40)/(4)=10s` Maximum Distance `=40 xx 10-1/2 xx 4 xx (10)^(2)=400-200=200m` |
|