Two bolcks A & B are connected by a spring of stiffness 512N//m and placed on a smooth horizontal surface. Initially the spring has its equilibrium length. The indicated velocities are imparted to A & B. Find the maximum extension in the spring?

Two bolcks A & B are connected by a spring of stiffness 512N//m and pl

1.	Two bolcks A & B are connected by a spring of stiffness 512N//m and placed on a smooth horizontal surface. Initially the spring has its equilibrium length. The indicated velocities are imparted to A & B. Find the maximum extension in the spring?
Answer» Solution :USING centre of MASS frome of refrence, we can say that `(1)/(2)muv_(rel)^(2)=(1)/(2)kx^(2)` [Here `mu=(m_(1)m_(2))/(m_(1)+m_(2))` (REDUCED mass)] `rArr((3xx6)/(3+6))(1.8+2.2)^(2)=512x^(2)` `rArr(2)(4)^(2)=512x^(2)` `rArrx=(1)/(4)m=25m`