1.

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts runing in a direction pependicular to AB with velocity v_(1).The boy at A starts runing simultaneously with velocity is v and catches the other boy is time t, where t is

Answer»

`a// SQRT(V^(2)+v_(1)^(2))`
`(a)/(sqrt(v^(2)-v_(1)^(2)))`
`a//(v-v_(1))`
`a(v+v_(1))`

Answer :B


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