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Two capacitors have a capacitance of `5 muF` when connected in parallel and `1.2 muF` when connected in series. Calculate their capacitance.

Answer» Correct Answer - `2 muF , 3 muF`
Let two capacitances be `C_(1)` and `C_(2)`
`C_(1) + C_(2) = 5 muF` and `(C_(1) C_(2))/(C_(1) + C_(2)) = 1.2 muF`
On solving, we get
`C_(1) = 2 muF, C_(2) = 3 muF`


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