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Two capacitors of `2 muF` and `3 mu F` are joined in series. The outer plate of second capacitor is earthed. Find out the potential and charge of the inner plate of each capacitor. |
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Answer» Correct Answer - `400 V, 400 V , 1.2xx10^(-3) C` We find `V_(1) = 600` volt and `v_(2) = 400` volt. As outer plate of first capacitor is at `1000`volt, its inner plate must be at `1000-600 = 400` volt Further, as outer plate of second capacitor is earthed , i.e., at zero potential, therefore inner plate of second capacitor must be at `400-0 = 400` volt Charge on inner plate of each condenser `q = C_(1) V_(1) = (2xx10^(-6))xx600 = 1.2xx10^(-3) C` |
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