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Two capacitors of `3 pF` and `6pF` are connected in series and a potential difference of `5000 V` is applied across the combination. They are then disconnected and reconnected in parallel. The potential between the plates isA. 2250 VB. 1111 VC. `2.25xx10^(6)V`D. `1.1xx10^(6)V` |
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Answer» Correct Answer - B `Q=CsV=((C_(1)C_(2))/(C_(1)+C_(2)))V=10^(-8)C` In parallel, `V=Q/(C_(1)+C_(2))=10^(-8)/(9xx10^(-12))=1111V` |
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