Two capacitors of capacitance of `6 muF and 12 muF` are connected in series with a battery. The voltage across the `6 muF` capacitor is 2V. Compute the total battery voltage.

Two capacitors of capacitance of `6 muF and 12 muF` are connected in s

1.	Two capacitors of capacitance of `6 muF and 12 muF` are connected in series with a battery. The voltage across the `6 muF` capacitor is 2V. Compute the total battery voltage.
Answer» As capacitors are connected in series, charge on each capacitor must be same. Charge on `6 muF` capacitor = charge on `12 muC` capacitor `6xx10^(-6)xx2 = 12xx10^(-6)xx V_(2)` `V_(2) = (6xx2)/(12) = 1 vol t` Total battery voltage `= V_(1) + V_(2) = 2 + 1 = 3V`

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Two capacitors of capacitance of `6 muF and 12 muF` are connected in series with a battery. The voltage across the `6 muF` capacitor is 2V. Compute the total battery voltage.

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