Two capacitors of capacitances `10muF and 20muF` are connected in series across a potential difference of 100V. The potential difference across each capacitor is respectivelyA. 66.67 V, 33.33 VB. 60 V, 40 VC. 50 V, 50 VD. 90 V, 10 V

Two capacitors of capacitances `10muF and 20muF` are connected in seri

1.	Two capacitors of capacitances `10muF and 20muF` are connected in series across a potential difference of 100V. The potential difference across each capacitor is respectivelyA. 66.67 V, 33.33 VB. 60 V, 40 VC. 50 V, 50 VD. 90 V, 10 V
Answer» Correct Answer - A `V_(1)=Q/C_(1)=(VC_(2))/(C_(1)+C_(2))=(100xx20xx10^(-6))/(30xx10^(-6))` `=66.67V` `therefore" "V_(2) = V-V_(1)=100-66.67=33.33V`

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Two capacitors of capacitances `10muF and 20muF` are connected in series across a potential difference of 100V. The potential difference across each capacitor is respectivelyA. 66.67 V, 33.33 VB. 60 V, 40 VC. 50 V, 50 VD. 90 V, 10 V

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