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Two capacitors of capacitances 3 μF and 6 μF are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be (a) zero (b) 3 V (c) 4 V (d) 6 V |
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Answer» Correct Answer is: (c) 4 V Charges on the two capacitors are 36 μC and 72 μC. When they are connected in opposition, the total charge on the system = (72 - 36) μC = 36 μC. This is shared between the capacitors so that they acquire the same potential difference. Let this be V. (3 μF)V + (6 μF)V = 36 μC or V = 4 V. |
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