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    				| 1. | Two capacitors of equal capacitance `(C_(1)=C_(2))` are as shown in the figure. Initially, while the swithc is open (as shown) one of the capacitors is uncharged and the other carries charge `Q_(0)`. The energy stored in the charged capacitor is `U_(0).` Sometime after the switch is closed, the capacitors `C_(1)"and" C_(2)` carry charged `Q_(1)"and"Q_(2)` respectively, the energy stored in the capacitors are `U_(1)"and"U_(2)` respectively. Which of the following expression is correct? A. `Q_(0) =1/2(Q_(1)+Q_(2))`B. `U_(0)=U_(1)+U_(2)`C. `Q_(0)=1/2((U_(1))/(Q_(1))+U_(2)/Q_(2))D. `Q=Q_(2)` | 
| Answer» Correct Answer - `(A,D)` | |